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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。
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用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）2 q2 }, f" R) f5 g3 }( {
( J( i6 n% L3 f8 M, G) f 第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
7 T7 X. T y, `; x
0 ^9 P8 b3 c8 n( @ 第二行：O X X O O OX O X （第二行开始出现洞）
) r7 C! ]& \# ]" o' ?* e
$ c! @1 n7 p* l 第三行：O X O X X6 B `9 M( g& ]- y- W" J# }% P- p
* h8 d+ \. d3 t' `; ?/ ], D( l# y
第四行：O X X0 m' j2 x; [' b6 v! c
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第五行： X- {' ]" W& y% O" w9 A
" a2 C0 M" _# `, A1 N9 s 那么新写出来的大路是怎么样的呢？' r; j7 Y, n+ a3 X2 Z$ o4 i
+ u% s" D8 O7 z' }6 w+ I 记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。
1 r2 [6 D7 x) ~% q( P4 C# f7 t) |* j* A- R6 L8 h) @) r
如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）0 h! i0 U; @" ~9 P+ N+ a4 R( O2 E
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第一行：OXXOXOXO OXOOX（第一行不再是单跳了）
2 f% _: w; o. p5 [
, N' O1 c) [6 F8 k2 i& W 第二行：OOXXXOOX XXXXX （第二行也是全满的）4 c) F+ Z" @1 [( g, y0 S7 Y4 G
' q! y) K9 o0 ^2 r. [ 第三行：OX OX XO XOOX （第三行才出现洞）
: G: z" @4 O/ A- r( l+ X& G- l" C3 ^$ ^% R
第四行：O XO O XXX + w' A6 j% h; }; u
% u" }, m& I4 v2 ]) l% o" b 第五行： O- p# {6 \6 C& t2 g; z& x7 J7 N: Z# S
4 E0 }; s! _ H. e# z% Z
通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。% ]5 S7 r6 I7 ^7 X5 }' u
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大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。
9 f& T1 ^6 j3 h0 j
8 ^1 a4 U: x( ^( G% h( e/ q 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。
# O5 k& m$ b) l: F8 i& L' O |
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