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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
3 c" P5 o8 e r- {" ~/ k
6 d4 y! N* s4 g* @7 o4 y 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)% r! O# t, J, `% ?; P, G2 u
! C+ ~& M* U9 X# b) M+ g( S. ` 第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)9 _: b0 ^' f* o3 g2 j; S
, G0 c# ]8 R. X5 U. f8 B) _( k1 V* j
第二行:O X X O O OX O X (第二行开始出现洞)
( H" N/ z, z) S! p/ x0 t2 u4 q0 h( m3 k# Y: U# \; o
第三行:O X O X X+ I Z$ f- T8 G% h
& E% a; \" ~+ g8 t4 q 第四行:O X X
& h5 c. Z* V. ]
* N1 v, U0 n3 N, c8 w" B% o( d 第五行: X% M0 A& b% C* y1 I0 u+ m2 O
. P* a+ L' d' n1 E" ]5 C
那么新写出来的大路是怎么样的呢?
# k- H, R4 L' `& }6 a2 z% p- {+ ?1 y h: q
记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。
' L# I* ?$ F$ l: Z A. [1 O6 F" d1 Q9 \8 l7 F
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
$ a1 [' T9 I6 p3 p# O
" D/ Z0 U3 @6 n$ B$ [" ?. Z# ^ 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
) r/ m6 b, [' k1 G% ^" Y, `
+ I d. V: Y l 第二行:OOXXXOOX XXXXX (第二行也是全满的)
' R' G+ [. ^3 g* s- x* T. V, S4 e) j2 l2 J) p3 K) o" t: W
第三行:OX OX XO XOOX (第三行才出现洞)) N+ x9 x9 [6 d1 N+ _8 y: W
! U# i% {8 g+ ~% ] 第四行:O XO O XXX
% g. ]3 `" i' s# w8 B1 l4 m0 W
2 }& S; x" E1 T- ?. n' v: ~ 第五行: O# \: {0 J/ J; e: r
6 p9 s6 z H# P9 _' G$ M 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。
) ~3 ?" R' `5 i0 ?+ M! B2 ? c+ w
/ W. H2 I6 k J( R% ~- ^# S 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。
/ `+ j" T0 G2 d+ r3 ^
/ q3 j3 a" N9 C. _% ~8 v 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。7 n" m' v8 t6 q9 ]
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