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[打法交流] 近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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1#
百家乐蒙特卡洛战术,需要纸和笔。但是不很难。
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(1) 首先写「 1 2 3 」的数列。. G" Z2 J! ~+ s& L1 u% }" O( ]

( ^# V! q! m( p* y9 K6 ?(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。" U' ?. p) X1 e  H# |3 F
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。1 }1 W2 l1 O( s8 P0 m4 v9 f
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(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。% F- b# L) |1 f1 A9 c

# X" v1 p- G  F4 h# P(5) 如果数列所有的数字都消了就代表结束。
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(6) 想继续的话,回到 (1) 。
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蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。
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二合一战术) w1 F0 E) j9 W1 S

, u; S# h% ]7 I/ q( Q. ]% T这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。
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; s8 B3 @% j) m: l$ _譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。
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反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?
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儘管结果是 2 胜 4 败,共计收支是一加一减等于零。  O' ~2 D. ?& }: h6 L8 A7 V
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这方法我试了不咋地,你们可能可以?# P4 ^* m: z( w4 F
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2#
百家乐玩家可以来了解一下哦
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听着就复杂,谁研究出来的
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4#
这个战术也是来看看了解下的了啊
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主题回复处广告图案-天策传媒
我不相信什么战术,我只相信自己的运气。
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6#
看到第三条时我就看不懂了啊
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战术也是要看有没有用的呀
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看来要认真学习了,学好了就有饭吃
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9#
战术方面已经好久没有碰过了啦
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那也是要好好关注这方面的了
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11#
这战术也不是每个人都能用得上的吧
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这个战术我以前也是听说过的
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其实只要懂大数法则就不会信这东东
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14#
这个真的要仔细来研究下哦
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:) :( :D :'( :@ :o
:P :$ ;P :L :Q :lol
:loveliness: :funk: :curse: :dizzy: :shutup: :sleepy:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory:
:) :( :D :'( :@ :o
:P :$ ;P :L :Q :lol
:loveliness: :funk: :curse: :dizzy: :shutup: :sleepy:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
:hug: :victory: :time: :kiss: :handshake: :call:
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:hug: :victory: :time: :kiss: :handshake:
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