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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。
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1 h, t% a+ K# ?: B0 i9 @; @* {1 I1 r(1) 首先写「 1 2 3 」的数列。
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8 Q/ k$ A9 G$ D& b6 m: t(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。& [! {) l# u3 {. A7 `6 b8 p- J# a
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。3 }! }! o2 z7 N/ f, _/ x
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(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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+ @5 Q7 d- f8 g- k5 J; E(5) 如果数列所有的数字都消了就代表结束。
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(6) 想继续的话,回到 (1) 。" k& }3 _7 q9 w" K& t* p
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蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。
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: j- p3 k* W: S& a6 ?4 a$ W这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。. P4 \" o3 i% a. m
. ^) T* Z$ O; v O" X& j譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。# M9 V( u: H' ~6 n" }$ b- i4 s' c
( `7 l* [; d0 M, U9 D& ]1 J反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?2 p4 {7 ]4 h& Q! s
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儘管结果是 2 胜 4 败,共计收支是一加一减等于零。
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这方法我试了不咋地,你们可能可以?
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