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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
- \4 i5 o1 @+ v
9 v0 I/ T) q2 i' b4 r 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
- q1 t9 {- @. y
+ u: ^, I9 ^# u, h: F5 g 第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
0 L2 X# U# s, k& s; o
1 R4 |6 b+ Y! I1 ]& a/ w, E3 ~. c3 J 第二行:O X X O O OX O X (第二行开始出现洞)3 I/ R1 p' h# l+ H5 H* g
8 }% F; d" `, i0 C 第三行:O X O X X
% P, R' }9 t3 \3 K. I4 Y2 I- N
第四行:O X X/ e( g+ b4 c G& K1 ?5 _# }
* I w0 {$ e. ^* V0 `
第五行: X
* S! [$ O0 w) A6 c" L" l- i4 M6 e+ \
那么新写出来的大路是怎么样的呢?8 |. c9 T! Z. V l( n
8 k8 X, [7 p- s* Z 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。1 v5 c% a- E5 c D
3 j3 o8 z$ `* B8 i( e, g/ K ?& d) w 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
% a7 @9 W' F9 @, r" h
* m% R" L3 n; H' l6 ]. F: L 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)1 a& e3 e" e; Y% Z
; ^$ f2 Z# l5 |6 C 第二行:OOXXXOOX XXXXX (第二行也是全满的)& t: o2 u" L1 O( z/ ^- {
# t, u9 m( B0 {, l) {1 T) Y5 O 第三行:OX OX XO XOOX (第三行才出现洞)) J& k2 n; J4 I/ z
; O Q8 P( t& {% I! t0 S 第四行:O XO O XXX
% M) }2 x+ n$ A J
# i- T" _. b5 E: x; d 第五行: O
$ Y7 D+ q+ Q8 D/ w+ B
( g6 [" S' J/ |" |3 ` 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。, ?* I5 Z& Q) [. J! E
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大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。
9 }2 R* P" n% O7 B8 O
' B/ m8 I4 t- \. C; m 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。
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