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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
/ ?& d2 {: b1 k" |4 @
% c4 C" n- J. |, z0 A+ ]" \ 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的), @% F4 Z: ^5 W" t7 i/ k
/ B: p3 |) k) ?$ ^" Y9 N- M" S
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
( v2 T" H( `+ n* J1 y- h9 G. e" w. T% C! W( r& @6 G' k" }
第二行:O X X O O OX O X (第二行开始出现洞): g6 p1 U% S4 w6 \
; T9 E# N0 d% D* w 第三行:O X O X X: s5 Z6 z5 X- c) i
: P$ c1 }) y+ d$ n* d7 I' p5 ^ 第四行:O X X5 s. d/ e0 ~* \$ s) ?( P$ o8 ]
% a% _3 l" O! M7 F: y
第五行: X n5 W U& P8 D" X. |3 q4 Q9 t% p
; |, v. J( x) }3 Z# v2 I. o7 `2 O 那么新写出来的大路是怎么样的呢?
/ ?/ j5 Y! q& e; `7 L/ B- j! h3 Y* O# O. D1 f( C
记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。; T% |& ]) ?/ h) t& x
) c% S& x: l9 @& j( G* k/ l 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)! T6 p# d d2 U
" H+ N: r# r9 R6 ]+ e 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
; x! {. c( \+ H
! \% Q2 k& [6 X9 m: J 第二行:OOXXXOOX XXXXX (第二行也是全满的), x+ d# O" E) q! @! ^. w3 z" D/ R
' X; H: b( q' l) Z% K, u9 P% w9 M 第三行:OX OX XO XOOX (第三行才出现洞)) C3 K: x- e) u9 F4 @4 h
2 a$ L% V# c1 w0 {( I 第四行:O XO O XXX
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第五行: O
3 V0 L2 a$ Y, K5 D0 H( M( ?' E* U9 A, |/ C' q7 J
通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。+ |, Q. h. T! ?& a9 @
! q1 d: l+ t b$ f3 R4 z# L 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。) X4 }6 s- E5 `! Z% J" E& i0 ~
/ m, r! ?! T0 d* L! J 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。6 x' }+ v U# }: ]* T/ r
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