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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O/ D3 z/ C& S4 }6 B
% \ u$ W& w ?/ D发现了一个有趣的现象，% t, w1 W' u: V; u
每一条大路，3 I6 V, @ T$ L# a' z6 y3 t! t
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
: Z+ ]0 d; \( L按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
! F) s. P$ v6 w. X按4珠路排列，有4种不同的路数
! B) e. [, f U' K6 @$ b g按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C) H7 ]. v% T& W
什么意思呢，可能大家一时不清楚，
; U* E/ Z1 w7 o" b5 Q" i& d- h+ N我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
) q1 l o3 x7 [# Z假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
4 K7 L2 R x% e4 ^* F12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h1 ~* R, }! `" Y
够极端了吧
( w) D! e/ w: n! T8 l按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F- G) I$ ?3 m8 D! P9 ~
如果我们去掉第一口，就会出现完全相反的结果：
/ R4 l7 G2 C, A3 U21212121212121212121212121212121
R3 \3 M% C8 i/ b" O变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C3 I% |& n- |7 @* K: F* j, N4 n3 g
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
. g- K$ K0 J1 o4 `7 D9 B所以每一条大路，! R6 V# q$ h. c; z% O
- z4 N) u7 K2 S( | \按2珠路排列，有2种不同的路数。
8 K6 m' D7 i7 ~$ `% O8 V再举一个列子：4 p$ V- [& K5 c1 {
大路：122122122122122122。。。$ |" i6 O- V# D, I6 p! }1 H
按三珠路排列：- i6 x, a2 P0 w/ g0 p8 E0 b1 l
122，122，122，122，122，122。。。
7 C1 C" K! u2 c- m, }, V去掉第一口，变成：6 G2 V! \" L' c" k: d. C, v' i$ N& L4 h
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M+ q/ g! `! V5 f
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
" R. {/ x, v s; I$ ]0 J" M$ T212，212，212，212，212，: y& l, B; I6 e- m. J# c) `% L1 [1 b, O, i, K( L2 Y* {
去掉3口，又返回122，122，122，了" N; ?9 J& a( L, G# m' P
所以每一条大路，
( h, i& m1 O0 [3 c! w' N. p按3珠路排列，有3种不同的路数。
3 t( }* P: i1 x+ g3 m同理：按N珠路排列，有N种不同的路数。" t( N) u0 h0 ~& f. @
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
- n! J/ e) M1 x" N3 J1 U1 b字串83 L: R) G1 V- s2 Y+ Y
: { @/ G4 a5 N+ N' V- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
7 R. P3 F( J1 c0 o/ ~1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
0 {( P) e$ v7 w5 m) Q/ R- b C+ }2、为三多理论提供了下注的多面性奠定基础。9 A/ O6 C b$ j' U* _( f
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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