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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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8 w$ b- h Y6 Q- h2 m 假设大路开这样的路:
' b, h, h' G& C) [& H' Z; {0 u) r2 n. b. w0 p# ?9 i5 W
12121212121212121212121212121212。1 @$ X h% m0 C3 Z, v
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按2珠路,就是BPBPBPBPBP。9 Q( B X8 x2 d3 Q" \
$ x" B4 p q- N( l3 ]- U% a4 \! I
如果我们去掉第一口,就会出现完全相反的结果:
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21212121212121212121212121212121。9 |8 ~* a/ z3 |. @! S- x
+ t' ?. u% n- e
变成了PBPBPBPBPB。4 v& A& r" X7 Y7 P' o
" w: h' f5 v1 X+ m 如果我们再去掉一口,又返回第一种情况了。/ X7 U6 r8 P; _' z
+ D* Z) ^8 L( ^- ?4 c1 }1 p 所以每一条大路,按2珠路排列,有2种不同的路数。% B7 i) S. y. ~
7 Z* c* }" |1 u# Y1 U* m
再举一个列子:7 |9 H! h9 R/ L4 f! M" t9 G
7 S, U! q4 r6 i" U 大路:122122122122122122。
& d, ]" h5 u+ z& m* ~
; r8 x, @3 F6 {5 C 按三珠路排列:; @/ \# x& [- G$ Q) |* S, y
. `7 m0 W) u& _; X! d8 C+ r( Z 122,122,122,122,122,122。# l; L4 L" t0 `$ `- `$ D
* ^* Z* s' s5 |: l3 h7 x, Q1 a/ A3 @
去掉第一口,变成:: }* ]/ c s6 J( K% A
+ x* r6 C, o" d. E% h: H' v9 @7 l 221,221,221,221,221,去掉前2口,变成:
( A% r3 o7 ^! E* ?0 Y5 `8 ~) W2 w) E ?6 q
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。# k3 G5 b( |0 [9 j* W, G% L
& l; |6 r7 Q' Z1 q0 L+ F 同理:按N珠路排列,有N种不同的路数。
9 R( d0 U" `+ X) s) `/ W+ {5 I0 [+ q; N6 y' ^7 S
我提出这个的意义在于:
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6 m4 v" B& n5 Y8 i 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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. [ p/ R+ @5 l 2、为三多理论提供了下注的多面性奠定基础。" W" ^# c: d7 U
* {" p4 v7 @& z( D: `$ i
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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