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[打法交流]
分享3d杀尾秘籍 助您轻松预测和值（二）（转）
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(六)遗左排除和尾
6 B2 E0 o, L: U5 m5 B" ~在号码和值尾的分布图上，看每期出现的和值尾左边遗漏的期数是多少，这个期数的尾，就是下一期我们可以排除的和值尾。) I9 u4 V% m- h5 [' ?2 a5 `; d5 H
(七)对码和排除和尾
- [* f) A4 O9 b% c05、16、27、38、49，每两个数合起来它就是对码。当出现0的时候，我们取它的对码就是5，某期开出的奖号是072，那么百位的0的对码就是个5，十位的7对码是2，个位的2对码就是7，那么这就是它的对码，把它的对码三个数给相加起来就是14，而这个14，我们是不看它十位的，我们只看它的尾，尾就是4，用它的尾来排除下一期的和值尾。也就是说下一期可以排除尾4的和值，尾4其中包括小4、14以及24点的和值。( {1 A1 }: p( O3 R4 y. \
(八)百位对码排除和尾- A( j! L0 ?( z$ x4 `& e. l
在0到9十个数字当中，0和5、1和6、2和7、3和8、4和9，这都是对码。那么也就是说当出现这个数字，不管它是几的时候，我们就看它的对码是什么，那么这个对码就是下一期可以排除的和值尾。9 J: j7 G0 r# Q4 K, ^- _9 Z4 p4 V/ W6 b
(九)间距排除和尾
( z1 _! z1 x8 j6 Q/ L4 E- f4 d我们用上下两期的和值，我们只取它的尾数，相减出来的差就是间距，那么得出来的这个数就是下一期我们可以排除的和值尾。- F7 P6 R" N! @' c, f+ C
(十)跨度乘和尾排除和尾. D3 H+ T- s1 M' F* N! N7 e
用上一期奖号的跨度和和尾相乘，那么得出的数就是下一期可以排除的和尾，但是如果乘出来的这个数如果是一个两位数的话，那么我们就把这两位数再相加，相加起来的和就是下一期可以排除的。- |1 [! u5 Q: Q9 P0 _- ?0 I
(十一)奖号十位平方和排除和尾
& ~1 i: x9 i( }5 Y! l3 \' t! n我们把上一期奖号的十位进行平方和运算，平方和的尾是什么，那么下一期就可以排除什么和值尾。2 Q: s! o' n5 j2 R, w& {+ {
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