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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O* H' X. \, H# R7 d3 w
! s0 S) c2 y; }
发现了一个有趣的现象,( m. @2 f$ m) |( X- H& y1 |6 }7 Q
每一条大路,
( d, q+ s; C, k0 x, R按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f
, c6 M' _: C" b0 t2 Y$ c按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z6 S% p  i& P7 S6 j1 V  e' Z
按4珠路排列,有4种不同的路数
: z, m& }8 y+ _4 n. d$ p按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C7 `& l9 q5 i" \9 m4 M7 y
什么意思呢,可能大家一时不清楚,
. b0 ]% O0 O: x9 j- |; A/ c我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l5 q/ t7 Q* q5 U; q  C
假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u
$ p# \' o0 J+ z$ J12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h0 |6 d( k% x+ D) z" [; O
够极端了吧0 w3 N+ R; I* R" D8 {9 F& V
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F5 E9 r  G1 p; K' P" f# W
如果我们去掉第一口,就会出现完全相反的结果:: C' ?0 Z2 B* ^" j% n. C; a9 L
21212121212121212121212121212121: d, E7 k$ `! z: V
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
0 C8 E" s0 W2 S/ i如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
, \) I' c1 V9 T. ~所以每一条大路,! R6 V# q$ h. c; z% O' \& G9 f; c+ V; v0 L4 f& R2 F
按2珠路排列,有2种不同的路数。3 k: e" z3 u1 l) M
再举一个列子:
3 q# w" ~" E/ j5 P大路:122122122122122122。。。& M6 v& l- C& q# S
按三珠路排列:$ K- k) l9 E+ w% @5 c1 j0 j
122,122,122,122,122,122。。。) j" P# F  M5 Q5 m7 y% i
去掉第一口,变成:6 G2 V! \" L' c" k: d/ B8 d2 n$ O( Q6 g8 o
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
' S9 F+ u) N) P  p' z去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W9 v9 J; r5 U4 s/ j% q6 c
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `
9 H! X+ }& ~! l( y/ [去掉3口,又返回122,122,122,了( R% M, G  o* A) s
所以每一条大路,
. ~$ e  m% j6 Y( A6 U; E按3珠路排列,有3种不同的路数。
; a5 ?+ f& T. {. L8 T9 p; N同理:按N珠路排列,有N种不同的路数。
& m% a2 l8 H; F1 l我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O3 @7 X7 }, w0 _% d, ^& B
字串83 L: R) G1 V- s2 Y+ Y% K( x+ d, n/ p2 ]) @% \6 O5 H
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
! `& I! ?' ]$ x1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
' [0 h% x' G: U2、为三多理论提供了下注的多面性奠定基础。
7 P* g3 K  k& Z* T4 J2 C: u# [3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路." ]& j" }  ]( w6 h0 S5 o

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