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0 ~* N9 U$ I2 b: Y# m
* t9 u' ?2 s% M/ s$ x' |通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。+ v, s" `- I D# V0 B g# @
4 \' R! j, R4 |& k 假设大路开这样的路:9 x8 o- K% T3 O
: Y( j+ ]$ b0 O4 M* Y
12121212121212121212121212121212。
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9 e$ F. }& j& i$ \6 b: i, [: ^4 E 按2珠路,就是BPBPBPBPBP。
' t5 N3 P0 J' ?% c
. i$ W. t5 ^1 X. Y: P5 {7 f- N; u# }' } 如果我们去掉第一口,就会出现完全相反的结果:+ Z! {; e; w+ S; x+ S) Q
6 k8 ~+ Y% J4 y3 q# R; e) s+ z
21212121212121212121212121212121。# p. H: Q | B* D5 ]$ G
- V( O2 y% l t. q0 U
变成了PBPBPBPBPB。" v9 P' k" h9 ^9 b6 c" f2 T
) H% H9 J' W- p+ k1 G' d; u 如果我们再去掉一口,又返回第一种情况了。
. l& O/ h0 J7 y8 Y& S
3 q. A! x5 w6 ^4 }, o+ I6 ^ 所以每一条大路,按2珠路排列,有2种不同的路数。% I' r9 o2 [* `% q4 O. e
$ V4 d/ y$ V% _0 |6 X
再举一个列子:) e4 W1 A0 R6 G0 c) V9 Y& K
4 s4 i4 y1 @+ K- m
大路:122122122122122122。
" N9 Y# B, {- G8 h
6 ^0 D! C/ ]1 ^; f0 M 按三珠路排列:
5 E1 g' [2 w0 Z$ u' }; D- E: p8 q9 T& Z" G9 r6 m
122,122,122,122,122,122。
5 Q& T# P$ Y1 i
! ~& {5 f8 D% b _6 W# B D 去掉第一口,变成:3 X `, G4 k# {6 `, P* I) h
9 p C& n, l* H, \
221,221,221,221,221,去掉前2口,变成:
0 @( }$ T1 b' y9 w0 J3 G& o( R
3 J4 Q+ ^) O% E& S2 W7 z0 ? 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。5 m1 ^: g" H4 ^# P: ?; i2 v
) I6 K+ N3 H: s+ q$ x
同理:按N珠路排列,有N种不同的路数。4 B* I* s5 z) P
7 C7 u- {( ]! n6 u% c5 s0 m# K 我提出这个的意义在于:9 B( j! g! H4 m9 ]& }2 u
# b& \6 u1 z$ l' @# A9 e" _ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
6 C; e1 z, }, `9 v: {6 K) C' P& ^! U
2、为三多理论提供了下注的多面性奠定基础。. L3 [7 ~# S/ C0 ?/ \2 g4 W5 t
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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