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[lastpost] => 2637662 百家乐没有不会断的缆,但是...-转载 1711637758 yubuluowang
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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。4 w6 g; @: g9 \
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(1) 首先写「 1 2 3 」的数列。
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6 w6 Q% D/ p, O) d(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。; o* u' z# P( W
& V% l3 B! E0 r1 j* ](3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。
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(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。0 }) R0 R+ J$ a* O) D: _
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(5) 如果数列所有的数字都消了就代表结束。
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(6) 想继续的话,回到 (1) 。* U, N3 h3 k( i3 a9 C' a& `
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蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。
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二合一战术
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这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。
( ~/ j' J5 C" {8 G+ c
- T; l1 h, |% S' V- ~" }$ S譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。8 h. C" z6 a1 y( \7 z( i3 X
- V. f( X+ j' T9 q反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?
' y% q+ _' s1 e b1 o8 z) b4 e' i- U1 j) E
儘管结果是 2 胜 4 败,共计收支是一加一减等于零。8 ^2 D1 v- \2 H, f; y- j
# {: F; w+ M! D' _1 ]' X: Z" F( [这方法我试了不咋地,你们可能可以?
' ^2 w8 g" N, X0 L7 U( t7 i3 p- j& M' I$ C `: M
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