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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
" b) x* K% q1 }7 ~0 Q: y$ S! d4 Z$ j& \3 C0 \0 l! ]
发现了一个有趣的现象，# K9 P' s$ J7 c' \ a1 i
每一条大路，
! r! R" f7 d. X; y按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f" b) N4 j2 m; m) A' t
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
E. }. ]& ]! R0 L; J按4珠路排列，有4种不同的路数
: P7 W8 B8 \$ J* [- {% f按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
8 R0 ?) a" `+ ^- }; K什么意思呢，可能大家一时不清楚，
" P9 v) M9 x( y. m( n2 @: T# ?/ I7 @我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l+ Y2 u, d9 V2 z4 x' R. c. u4 ~
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u& `2 u, @/ V$ N% u+ w g2 m
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h* }' y1 X' O2 X* [9 ~
够极端了吧 _2 I# _! `4 u; V, m1 k+ V
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
, |, l# T- a( F6 {+ u. P9 I如果我们去掉第一口，就会出现完全相反的结果：2 U/ _& O- y6 p, C
21212121212121212121212121212121
, C: P) E+ _/ W6 M2 }3 j K变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
& z% U \) j5 f& N8 ]如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O" Q1 f( A/ o8 _+ p9 [/ |2 |5 O
所以每一条大路，! R6 V# q$ h. c; z% O. w# o& f: s6 q* p7 Z: O) j$ B
按2珠路排列，有2种不同的路数。 c$ Q( R0 q' A8 A6 M1 L
再举一个列子：3 o) U4 W) b' m. \
大路：122122122122122122。。。
! K# w' p; a" f" z' r3 g+ z按三珠路排列：" m" [* u. s5 J* V) |4 B# v# n \( {
122，122，122，122，122，122。。。
! ?6 z. U1 h" L) W: N1 M$ d! W9 \! k去掉第一口，变成：6 G2 V! \" L' c" k: d
: P8 ~# P9 ~: R; D5 R; W5 c221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
9 y5 e( K% W6 n, B" S去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
0 `( `1 z0 f+ q- v4 B" t! ~+ _212，212，212，212，212，: y& l, B; I6 e- m. J# c) `$ W- m: W9 S% T6 y7 b! M' o
去掉3口，又返回122，122，122，了+ o# S; y4 y7 M
所以每一条大路，& }" f+ n$ \, {, B0 ^: I. L
按3珠路排列，有3种不同的路数。7 {& j9 ^3 R: X& { N7 X
同理：按N珠路排列，有N种不同的路数。
! n4 y+ b% ?7 E) F6 B- ?# p我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
0 m2 @6 m$ ~" `" h字串83 L: R) G1 V- s2 Y+ Y
+ J4 N2 u- d) B. E$ B" o; Q- p, d3 [6 U. s5 J' [0 {1 A" m' k( @0 e' P4 e! _# q- w
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |/ B1 V3 c P9 B8 }" a+ J+ C
2、为三多理论提供了下注的多面性奠定基础。! \# F2 p0 z( R2 K
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.- Z6 |2 f1 ]5 h. I9 T3 l: ?
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