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[lastpost] => 2655654 【E世博】6月7日投注流水2828元(单日流水) 1717869152 南相楚
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以下是输给那破游戏不甘心后的乱想..如有错误请提出或无视.. 首先是豹子问题8 t: ~6 ?8 Y0 ^5 v2 _
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因为太郁闷..所以从排列组合开始..3 m1 @" n5 Y1 @8 h5 ^4 R! f
4 q- ]9 E# ~1 x1 H8 @
假设直线A上有N个点,取任意点都有相同程度的概率.那么有2个取点者同时随即取点E,2者同时取得点E的概率是E/N*N
# U# \5 D' ?. F7 o% C$ K
4 P- M" V) [6 i; J. w那么豹子的出现概率是2/216=0.00926=0.926%6 o. ?/ H9 Y0 m+ J
6 P- R, O4 P7 T5 ?# v! m豹子的赔率是30那么收益期望为0.2778风险为99.074%5 O( ?% \* _; R6 ^& |
. K( \& F T6 o: N+ y8 \
连续2次出现率为42.67%的负4次方(大概是大型超市抽奖活动的特等奖的概率..有信心的可以玩下) _" M8 u0 w3 F' j4 ?2 q
/ L9 ? q3 a% G$ A+ o: U
在是压大小问题.
+ f; m" A) e' [' J9 ]8 b+ F3 w3 w3 d7 b+ _- l: J2 m
根据以上得出每组大小的概率是49%..
1 U% ] `+ p2 q7 I% H
; F& z) }0 A( p由此可见..压大小就总合来说是必败的
" r: E& A+ G4 Q' V- ?4 } c6 U1 L8 r- L' [
心理学中有个叫赌徒效应还是啥啥的..是说随即序列发生一个事件的概率与之前发生的事件无关。即发生的概率并没有因先前发生的事件而增加。% G$ g1 P# j1 l+ Q; k
2 v M$ R9 T1 ?9 v, Y; T( j. g也就是说,压大小实际上永远就是49%概率压对。' _; N- e8 ^6 z" l& a9 I/ `# i
, }- R$ e" s _4 C
并非这次压错了.下次就是50%了
6 Q' Z( H9 K- K4 ^2 W
& n! k5 D$ u5 J' }6 R& X; H由此可见压大小以综合来说必输.压豹子其收益价与风险值不成比列。
5 u, ^8 a8 A; D6 W7 R k6 s o& i. m) Z
根据以上分析.还是奉劝大家!远离DB!
1 k& m H& E5 g* E" B( o" x2 a% K+ p8 Z& V n7 N; V
还有..以上是有实际验证的~昨天赌了上百回资金流动大概有成千上万..损失了进两百
, {6 t7 o* A& O& _
7 c6 l* {0 J9 t, c( O今天中午又赌了N次..资金流动上千..损失了30左右..均与以上概率成比例~ 嘛- -偶赌的还算比较厉害了..输的惨就不去说了~~那位上千的全没了
- D& y+ [5 h5 S! l
& q* ~% d. G6 a6 U偶决定在也不赌了~真的...
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必输的东西也是要来旁观了啊,这么的东西还是值得学学的 |
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