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[lastpost] => 2773627 【星宝】10月14日投注流水75600元 1760510187 rainwang
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5 R' y, o' m1 v' u; \" u通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。; ^2 I* A2 S! W( _
' q( s v7 F* A6 f, H 假设大路开这样的路:' U, L, [: T# s! s0 T
. J8 ^8 l% l' {- o' S7 n) m+ q
12121212121212121212121212121212。6 p9 t7 R0 I7 J- I
1 i( k, ]; I E2 d7 w0 K 按2珠路,就是BPBPBPBPBP。/ i8 d3 e% ]6 x# ~7 J
, `# P) ~' X1 f0 D% b+ p- @
如果我们去掉第一口,就会出现完全相反的结果:
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( H1 Q" @. B! ~- G9 k 21212121212121212121212121212121。* `3 z: @. s% I& i
$ A& W! Y3 p/ X' H* O- d; q 变成了PBPBPBPBPB。
* e# t) y) E1 q2 _0 y. g
" e3 W% `0 E( J3 c( `5 X 如果我们再去掉一口,又返回第一种情况了。% Q$ z& B( ~3 M/ g
$ r7 `' z; x4 k( l# g, ]8 C# C 所以每一条大路,按2珠路排列,有2种不同的路数。! }9 j: z& ^! q: R# k+ y
3 J8 l" L; b8 l ~. R! ?8 I5 ~3 D6 y 再举一个列子:; h8 G, M8 F" ]
: N% R' O$ x! t; ~: l2 g, [* b( {1 [ 大路:122122122122122122。" G+ C7 f4 G( e+ j, D# o# W5 f- `; L
% u8 \, c+ L& x$ i, H" } 按三珠路排列:
0 r ` y7 s( V' B+ e: j+ k9 a1 g. F4 m6 A+ r/ C1 |, |2 x: s
122,122,122,122,122,122。
3 y$ ~: s8 R6 V
* y% J# V' `( I' [9 C 去掉第一口,变成:
( N6 J7 u) D; \9 q) J$ i* L+ y2 m& ]3 L, c: z9 h4 L1 w0 `
221,221,221,221,221,去掉前2口,变成:
9 s2 f6 H+ d1 c3 Z5 }/ V, M( y/ q9 F
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 b1 i0 c) I! U% s
& a; Y1 b3 t2 n+ h# y: M% x 同理:按N珠路排列,有N种不同的路数。
% l/ ~# f4 {7 {
; i( b' S8 \1 m% K1 H, H 我提出这个的意义在于:
% v$ G8 Y: N. P+ q, V: O+ h; z" V' D- W- G" |" R2 u X
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。' R' Y- ]/ K# e- A# h }% \: r" U) ^
2 U% l# ^( k5 V" d: {+ ` q( D
2、为三多理论提供了下注的多面性奠定基础。' J; i& F! o$ K( w# s8 w
) a- h* v% E4 X7 Y+ d# c4 Y9 d 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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