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W1 Q" A9 M1 ]: G* ~: A
- S+ |% m X& }3 D; F通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。8 {$ f' Q0 H! T9 E
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假设大路开这样的路:
% ]; `" {0 U. D& J; B! D V% P' C! |6 M0 ~8 T
12121212121212121212121212121212。
* N) W* y. }2 }7 ?" O. {
8 L2 ]9 p$ E) D( B0 ?( A4 R 按2珠路,就是BPBPBPBPBP。; |" `" c/ U) S. F U' x3 N
, B X0 ~# j7 @ 如果我们去掉第一口,就会出现完全相反的结果:
4 ^6 k; j# r+ A( G) M. [) E: ?6 H) h D a3 _: o: m" C; H
21212121212121212121212121212121。1 `* ?: `1 B. g/ ~0 a0 Z
. [% N. A( h3 Z, |) r; ^: C 变成了PBPBPBPBPB。
, C! S7 b {3 c$ e% z7 ^, Q: n1 m& v, p G4 w
如果我们再去掉一口,又返回第一种情况了。
) _; z! P- r8 V: l* e6 F! \# |! s+ V- a( D$ I7 j5 _) y
所以每一条大路,按2珠路排列,有2种不同的路数。0 Y2 F, g: v8 l3 V+ O
" S) f# F! u- c, [2 N: t6 X
再举一个列子:* d& O6 i3 J6 `6 m a3 F4 i
" k U* c( P: I* r4 P( R* j1 e 大路:122122122122122122。
" Q5 H2 a4 E5 j2 O! O q3 z
+ O+ A C. I, _, _& t3 p 按三珠路排列:) C/ [, k% Q, S( h. I
% v+ R4 A/ i1 l; p 122,122,122,122,122,122。
, ?- o U4 U3 b5 Y& F
) q u7 l; f' P# h; T) t 去掉第一口,变成:
6 j! {3 M& v5 O' t+ x$ |5 F: h( {
221,221,221,221,221,去掉前2口,变成:' ~, Z- I+ w1 U+ h, E! B" U: ]" ?
% ~7 e- w: D& Q8 P# r- u
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。0 v2 H! C: k% @, p* d, ]9 o) k: ?; c
& g. ]3 ?/ }, R. M' p 同理:按N珠路排列,有N种不同的路数。
" T0 w( l' s: m; u% E9 p5 l3 m! @+ `1 W
我提出这个的意义在于:) B$ v* |& a3 i5 L7 O
# |9 t- S& D( J; K3 v5 ^ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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* J% w3 g; z2 c8 `# @ 2、为三多理论提供了下注的多面性奠定基础。
5 {- G) |1 b. D% \# p7 a* u
/ M' K7 n1 h. {- c& q 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。2 f% _' Y) J- c. C( a" @" j' i X
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